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PprWoman

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Since: Sep 03, 2003
Posts: 4



(Msg. 1) Posted: Wed Sep 17, 2003 4:39 pm
Post subject: help with my math
Archived from groups: rec>gambling>poker (more info?)

can someone please show me how to solve this problem

B = [-sigma^2/(2*EV)]*

sigma =12
ev =1

thanks ppr

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Paul L. Schwartz

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Since: Jul 10, 2003
Posts: 40



(Msg. 2) Posted: Wed Sep 17, 2003 4:39 pm
Post subject: Re: help with my math [Login to view extended thread Info.]
Archived from groups: per prev. post (more info?)

"PprWoman" <pprwoman DeleteThis @aol.com> wrote in message
news:20030917123902.10815.00001147@mb-m29.aol.com...
> can someone please show me how to solve this problem
>
> B = [-sigma^2/(2*EV)]*
>
> sigma =12
> ev =1
>
> thanks ppr

I assume you want to calculate a value for B. Simply plug in the numbers:

B = [ - 12^2 / (2*1) ]

(I am not sure what the trailing "*" means. There should be a number or
letter following)

Simplifying:

B = [-144/2] = -72

(not sure if I am being to simple here but 12^2 mean 12*12 or 12 times 12)

Paul

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PprWoman

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Since: Sep 03, 2003
Posts: 4



(Msg. 3) Posted: Wed Sep 17, 2003 5:20 pm
Post subject: Re: help with my math [Login to view extended thread Info.]
Archived from groups: per prev. post (more info?)

its a formula to calculate my bankroll and i also got a negitive number. i
pulled this off 2+2 from brucez
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Paul L. Schwartz

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Since: Jul 10, 2003
Posts: 40



(Msg. 4) Posted: Wed Sep 17, 2003 5:20 pm
Post subject: Re: help with my math [Login to view extended thread Info.]
Archived from groups: per prev. post (more info?)

"PprWoman" <pprwoman.DeleteThis@aol.com> wrote in message
news:20030917132027.10780.00001027@mb-m29.aol.com...
> its a formula to calculate my bankroll and i also got a negitive number. i
> pulled this off 2+2 from brucez

I have taken a look at the post by Brucez on 2+2. You have mistated the
formula, which should be:

B = -(sigma^2/2*ev)ln(r)

where r is the risk of ruin. ln(r) is the natural logarithm. This value
can be looked up or computed using a scientific calculator. Let's assume
you want a maximum risk of ruin of 5% or 0.05 (and your values of sigma=12
and ev=1). The formula becomes:

B = - (12^2/(2*1))*ln(0.05) = -144/2 * (-2.996) = 215

If you are unfamiliar with logarithms here is a quick explanation. A
logarithm is simply an exponent defined by the equation (base)^(log x) = x.
In the case of the natural logarithm, the base is the constant e, a constant
which occurs naturaly in mathematics and nature. e is approximately equal
to 2.7183. For example, using common logarithms or base 10, log 100 = 2
because 10^2 = 100.

I hope this helps.

Paul
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Adam

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Since: Sep 03, 2003
Posts: 28



(Msg. 5) Posted: Wed Sep 17, 2003 5:33 pm
Post subject: Re: help with my math [Login to view extended thread Info.]
Archived from groups: per prev. post (more info?)

Maybe you should copy the whole post to put the calculation into context.
On Sep 17 2003 1:20PM, PprWoman wrote:

> its a formula to calculate my bankroll and i also got a negitive number. i
> pulled this off 2+2 from brucez

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